Quantum field

$$ \Psi(x)=\sum_i a_i^{-}\psi_i(x) $$

where:

According to this derivation of Susskind

the quantum field or, better said, its Hermitean conjugate $\Psi^{\dagger}(x)$, when applied to the empty state $|0\rangle$, it creates a single particle localized at position $x$.

Similarly,

$$ \Psi^{\dagger}(y)\Psi^{\dagger}(x)|0\rangle $$

is a two particle state, one at $x$ and one at $y$.

Moreover, here Susskind shows that $\int dx \Psi^{\dagger}(x)\Psi(x)=\sum_i N_i$, where $N_i$ is the number operator. So this integral represents an operator which gives us, when applied to a state, the total number of particles. Therefore, $\Psi^{\dagger}(x)\Psi(x)$ represents the "particle density", and it can be measured. Indeed, it is $\int_R dx \Psi^{\dagger}(x)\Psi(x)$, with $R$ a small region of space, what can be measured.

Also, he shows that in case that $\omega_i$ is the eigenvalue associated to $\psi_i$, then

$$ \hat{E}:=\int dx \Psi^{\dagger}(x)\hat{H}\Psi(x)=\sum_i N_i\omega_1 $$

where $\hat{H}$ is the Hamiltonian of the 1-particle system. So the operator $\hat{E}$ is the Hamiltonian of the quantum field theory.

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Author of the notes: Antonio J. Pan-Collantes

antonio.pan@uca.es


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